Image mapping using lookup tables [on hold]
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jblasius
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Published on 2013-10-22T17:12:49Z
Indexed on
2013/10/23
10:15 UTC
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I have an optimization problem.
I'm using a look-up table to map a pixel in an image:
for (uint32_t index = 0u; index < imgSize; index++)
{
img[ lt[ index ] ] = val;
}
Is there a faster way to do this, perhaps using a reinterpret_cast
or something like that?
I am accessing two different memory addresses, so what is the compiler doing?
One solution is to do a set of reads to access adjacent memory addresses.
struct mblock
{
uint32_t buf[10u];
};
mblock mb;
for (uint32_t index = 0u; index < imgSize; index += 10u)
{
mb = *reinterpret_cast<mblock*>(lt + index));
for (uint8_t i = 0u; i < 10u; i ++)
{
mb.buf[i] += img;
}
for (uint8_t i = 0u; i < 10u; i ++)
{
*( mb.buf[i] ) = val;
}
}
This speeds up the code because I'm separating the image access from the table look-up; the positions in the look-up table are adjacent.
I still get the image access problem as it is accessing random address positions.
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